Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.1 - Polar Coordinates - 8.1 Exercises - Page 593: 27

Answer

$(-\frac{5}{2}, -\frac{5\sqrt 3}{2})$

Work Step by Step

Step 1. Read the quantities from the figure given in the Exercise: $r=5, \theta=-\frac{2\pi}{3}$ Step 2. Convert to rectangular coordinates: $x=r\cdot cos\theta=5cos(-\frac{2\pi}{3})=-\frac{5}{2}$ and $y=r\cdot sin\theta=5sin(-\frac{2\pi}{3})=-\frac{5\sqrt 3}{2}$, thus the coordinates are $(-\frac{5}{2}, -\frac{5\sqrt 3}{2})$
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