Answer
$(3, \frac{3\pi}{2})$$(3, \frac{3\pi}{2})$
Work Step by Step
The point P, $(0, -3)$ lies on the y-axis
Change from rectangular to polar coordinates with
$r^2 = x^2 + y^2$ and $\tan θ = \frac{y}{x}$
$r^2 = 0 + (-3)^2$
$r = 3$
$\tan θ = \frac{-3}{0}$
θ is undefined, but since it is on the negative part of the y-axis, it will be $\frac{3\pi}{2}$
Thus the answer is $(3, \frac{3\pi}{2})$
