Answer
$(-\sqrt 3, 1)$
Work Step by Step
Step 1. Read the polar coordinates from the figure given in the Exercise: $r=2, \theta=\frac{5\pi}{6}$
Step 2. Convert from polar to rectangular coordinates: $x=r\cdot cos\theta=2cos\frac{5\pi}{6}=-2\times\frac{\sqrt 3}{2}=-\sqrt 3$ and $y=r\cdot sin\frac{5\pi}{6}=2\times1/2=1$ so the rectangular coordinates are $(-\sqrt 3, 1)$
