Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.1 - Polar Coordinates - 8.1 Exercises - Page 593: 29

Answer

The point in rectangular coordinates is $\Big(2\sqrt{3},2\Big)$

Work Step by Step

$(4,\pi/6)$ The point has $r=4$ and $\theta=\dfrac{\pi}{6}$. The formulas for converting polar to rectangular coordinates are $x=r\cos\theta$ and $y=r\sin\theta$. Substitute the known values into the formula to obtain $x$ and $y$: $x=r\cos\theta$ $x=(4)\cos\Big(\dfrac{\pi}{6}\Big)=(4)\Big(\dfrac{\sqrt{3}}{2}\Big)=2\sqrt{3}$ $y=r\sin\theta$ $y=(4)\sin\Big(\dfrac{\pi}{6}\Big)=(4)\Big(\dfrac{1}{2}\Big)=2$ The point in rectangular coordinates is $\Big(2\sqrt{3},2\Big)$
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