Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 544: 84

Answer

Verify the following identity: $tan(u) (sin(u))/(tan(u) + sin(u)) = (tan(u) - sin(u))/(tan(u) sin(u))$

Work Step by Step

Verify the following identity: $tan(u) (sin(u))/(tan(u) + sin(u)) = (tan(u) - sin(u))/(tan(u) sin(u))$ Cross multiply: $sin(u)^2 tan(u)^2 = ^?(tan(u) - sin(u)) (sin(u) + tan(u))$ Write tangent as sine/cosine: $sin(u)^2 ( (sin(u))/(cos(u)) ^2 ) = ^?((sin(u))/(cos(u)) - sin(u)) (sin(u) + (sin(u))/(cos(u)))$ $sin(u)^2 ((sin(u))/(cos(u)))^2 = (sin(u)^4)/(cos(u)^2)$: $(sin(u)^4)/(cos(u)^2) = ^?(((sin(u))/(cos(u))) - sin(u)) (sin(u) + ((sin(u))/(cos(u))))$ Put $(sin(u))/(cos(u)) - sin(u)$ over the common denominator $cos(u)$: $(sin(u))/(cos(u)) - sin(u) = (sin(u) - cos(u) sin(u))/(cos(u))$: $(sin(u)^4)/(cos(u)^2) = ^?(sin(u) - cos(u) sin(u))/(cos(u)) (sin(u) + (sin(u))/(cos(u)))$ Put $sin(u) + (sin(u))/(cos(u))$ over the common denominator $cos(u): sin(u) + (sin(u))/(cos(u)) = (sin(u) + cos(u) sin(u))/(cos(u))$: $(sin(u)^4)/(cos(u)^2) = ^?(sin(u) - cos(u) sin(u))/(cos(u)) (sin(u) + cos(u) sin(u))/(cos(u))$ $((sin(u) - cos(u) sin(u)) (sin(u) + cos(u) sin(u)))/(cos(u) cos(u)) = ((sin(u) - cos(u) sin(u)) (sin(u) + cos(u) sin(u)))/cos(u)^2$: $(sin(u)^4)/(cos(u)^2) = ^?((sin(u) - cos(u) sin(u)) (sin(u) + cos(u) sin(u)))/(cos(u)^2)$ Multiply both sides by $cos(u)^2$: $sin(u)^4 = ^?(sin(u) - cos(u) sin(u)) (sin(u) + cos(u) sin(u))$ Divide both sides by $sin(u)^2$: $sin(u)^2 = ^?-(cos(u) - 1) (1 + cos(u))$ $sin(u)^2 = 1 - cos(u)^2$: $1 - cos(u)^2 = ^?-(cos(u) - 1) (1 + cos(u))$ $-(cos(u) - 1) (1 + cos(u)) = 1 - cos(u)^2$: $1 - cos(u)^2 = ^?1 - cos(u)^2$ The left hand side and right hand side are identical, thus verifying the identity.
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