Answer
$tan\ u$
Work Step by Step
$\sqrt(x^2 - 1)$, $x = sec\ u$
We know that $1 + tan^2\ u=sec^2\ u$:
$\sqrt(x^2 - 1)=\sqrt(sec^2\ - 1)=\sqrt(tan^2\ u)=tan\ u$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 544: 91
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