Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 544: 90

Answer

$sec\ u$

Work Step by Step

$\sqrt(1 + x^2)$, $x =tan\ u$ We know that $1+tan^2\ u=sec^2\ u$ $\sqrt(1 + x^2)=\sqrt(1 + tan^2\ u)=\sqrt(sec^2\ u)=sec\ u$
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