Answer
$tan\ u$
Work Step by Step
$x/\sqrt (1 - x^2)$, $x = sin\ u$
$sin\ u/\sqrt (1 - sin^2\ u)=sin\ u/\sqrt (cos^2\ u)$, since $sin^2\ u+cos^2\ u=1$
$sin\ u/\sqrt (cos^2\ u)= sin\ u/cos\ u=tan\ u$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 544: 89
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