Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 7 - Section 7.1 - Trigonometric Identities - 7.1 Exercises - Page 544: 93

Answer

$3cos\ u$

Work Step by Step

$\sqrt(9 - x^2)$, $x = 3 sin\ u$ We know that $ cos^2\ u+sin^2\ u=1$: $\sqrt(9 - x^2)=\sqrt(9 - (3 sin\ u)^2)=\sqrt(9 - 9sin^2\ u)=3\sqrt(1 - sin^2\ u)=3\sqrt(cos^2\ u)=3cos\ u$
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