Answer
(a) $P=x(x+2)(x-2)(x^2+4)$
(b) $P=x(x+2)(x-2)(x+2i)(x-2i)$
Work Step by Step
(a) $P=x(x^4-16)=x(x^2-4)(x^2+4)=x(x+2)(x-2)(x^2+4)$
(b) $P=x(x+2)(x-2)(x+2i)(x-2i)$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 294: 70
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