Answer
(a) $P=(x-2)(x^2+2x+2)$
(b) $P=(x-2)(x+1+i)(x+1-i)$
Work Step by Step
(a) $P=x^3-8-2x+4=(x-2)(x^2+2x+4)-2(x-2)=(x-2)(x^2+2x+2)$
(b) $P=(x-2)(x+1+i)(x+1-i)$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 294: 66
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