Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 294: 69

Answer

(a) $P=(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)$ (b) $P=(x+2)(x-2)(x+1+\sqrt 3i)(x+1-\sqrt 3i)(x-1+\sqrt 3i)(x-1-\sqrt 3i)$

Work Step by Step

(a) $P=(x^3+8)(x^3-8)=(x+2)(x^2-2x+4)(x-2)(x^2+2x+4)$ (b) $P=(x+2)(x-2)(x+1+\sqrt 3i)(x+1-\sqrt 3i)(x-1+\sqrt 3i)(x-1-\sqrt 3i)$
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