Answer
$-1, 1\pm i$
Work Step by Step
$P=x^2(x^2-1)+2(x+1)=x^2(x+1)(x-1)+2(x+1)=(x+1)(x^3-x^2+2)
=(x+1)(x^3+1-x^2+1)=(x+1)[(x+1)(x^2-x+1)-(x^2-1)]
=(x+1)^2[(x^2-x+1)-(x-1)]=(x+1)^2(x^2-2x+2)$
Zeros $-1, 1\pm i$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 3 - Section 3.5 - Complex Zeros and the Fundamental Theorem of Algebra - 3.5 Exercises - Page 294: 60
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