Answer
$1,\pm2i,\pm\sqrt 3i$
Work Step by Step
1. List possible rational zeros $\pm1,\pm2,\pm3,\pm4,\pm6,\pm12$
2. Use synthetic division or remainder theorem to test some of the values.
3. We can find one rational zero at $x=1$ and the quotient as shown
$P(x)=(x-1)(x^4+7x^2+12)=(x-1)(x^2+4)(x^2+3)$
4. Solve the quadratic terms, we have all the zeros as
$1,\pm2i,\pm\sqrt 3i$