Answer
$\frac{A}{x-1} + \frac{B}{x+1} + \frac{Cx + D}{x^{2} + 1}$
Work Step by Step
$\frac{1}{x^{4} - 1}$
$\frac{1}{(x^{2} - 1)(x^{2} + 1)}$
$\frac{1}{(x - 1)(x+1)(x^{2} + 1)}$ = $\frac{A}{x-1} + \frac{B}{x+1} + \frac{Cx + D}{x^{2} + 1}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 10 - Section 10.7 - Partial Fractions - 10.7 Exercises - Page 750: 8
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