Answer
$\frac{2}{x} - \frac{1}{x+3}$
Work Step by Step
$\frac{x+6}{(x)(x+3)}$ = $\frac{A}{x} + \frac{B}{x+3}$
Multiply both sides by (x) (x+3)
$x+6 = A(x+3) + B (x)$
A + B = 1
3A = 6
Thus A = 2 and B = -1
$\frac{2}{x} - \frac{1}{x+3}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 10 - Section 10.7 - Partial Fractions - 10.7 Exercises - Page 750: 16
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