Answer
$\frac{-1}{x+2} + \frac{1}{x-2}$
Work Step by Step
$\frac{4}{(x^2 -4)}$ = $\frac{A}{x+2} + \frac{B}{x-2}$
Multiply both sides by (x+2) (x-2)
$4 = A(x-2) + B (x+2)$
$A + B = 0$
$-2A + 2B = 4$
Thus A = -1 and B = 1
$\frac{-1}{x+2} + \frac{1}{x-2}$
