Answer
$\frac{1}{x-1} + \frac{1}{x+1}$
Work Step by Step
$\frac{2x}{(x-1)(x+1)}$ = $\frac{A}{x-1} + \frac{B}{x+1}$
Multiply both sides by (x-1) (x+1)
$2x = A(x+1) + B (x-1)$
A + B = 2
A - B = 0
Thus A = 1 and B = 1
$\frac{1}{x-1} + \frac{1}{x+1}$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 10 - Section 10.7 - Partial Fractions - 10.7 Exercises - Page 750: 14
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