Answer
$\frac{3}{x-4} - \frac{2}{x+2}$
Work Step by Step
$\frac{x+14}{(x^2 - 2x - 8)}$ = $\frac{A}{x-4} + \frac{B}{x+2}$
Multiply both sides by (x+2) (x-4)
$x+14 = A(x+2) + B (x-4)$
$A + B = 1$
$2A - 4B = 14$
Thus A = 3 and B = -2
$\frac{3}{x-4} - \frac{2}{x+2}$
