Answer
$\frac{3}{x} - \frac{2}{x-4}$
Work Step by Step
$\frac{x-12}{(x^2 -4x)}$ = $\frac{A}{x} + \frac{B}{x-4}$
Multiply both sides by (x) (x-4)
$x-12 = A(x-4) + B (x)$
$A + B = 1$
$-4A = -12$
Thus A = 3 and B = -2
$\frac{3}{x} - \frac{2}{x-4}$