Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.7 - Partial Fractions - 10.7 Exercises - Page 750: 18

Answer

$\frac{3}{x} - \frac{2}{x-4}$

Work Step by Step

$\frac{x-12}{(x^2 -4x)}$ = $\frac{A}{x} + \frac{B}{x-4}$ Multiply both sides by (x) (x-4) $x-12 = A(x-4) + B (x)$ $A + B = 1$ $-4A = -12$ Thus A = 3 and B = -2 $\frac{3}{x} - \frac{2}{x-4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.