Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.7 - Partial Fractions - 10.7 Exercises - Page 750: 45

Answer

$A=\frac{a+b}{2}$ $B=\frac{a-b}{2}$

Work Step by Step

Step 1. Combine the right side of the equation to obtain: LHS=$\frac{A(x+1)+B(x-1)}{(x-1)(x+1)}=\frac{(A+B)x+(A-B)}{x^2-1}$ Step 2. Compare the above results with the left side to get: \begin{cases} A+B=a \\A-B=b \end{cases} Step 3. Add up the two equations to get $2A=a+b$, thus $A=\frac{a+b}{2}$ Step 4. Plug-in the above result to one of the equations to get $B=a-A=\frac{a-b}{2}$
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