Answer
$\frac{2}{x-3} - \frac{2}{x+3}$
Work Step by Step
$\frac{12}{(x^2 -9)}$ = $\frac{A}{x-3} + \frac{B}{x+3}$
Multiply both sides by (x-3) (x+3)
$12 = A(x+3) + B (x-3)$
A + B = 0
3A - 3B = 12
Thus A = 2 and B = -2
$\frac{2}{x-3} - \frac{2}{x+3}$
