Answer
$\frac{1}{x+2} + \frac{1}{x-1}$
Work Step by Step
$\frac{2x+1}{(x^2 + x - 2)}$ = $\frac{A}{x+2} + \frac{B}{x-1}$
Multiply both sides by (x+2) (x-1)
$2x+1 = A(x-1) + B (x+2)$
$A + B = 2$
$-A + 2B = 1$
Thus A = 1 and B = 1
$\frac{1}{x+2} + \frac{1}{x-1}$
