Answer
$A \approx60.9^\circ$
$B \approx42.8^\circ$
$C\approx 76.3^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $A=cos^{-1}(\frac{(7)^2+(10)^2-(9)^2}{2(7)(10)})\approx60.9^\circ$
2. Use the Law of Cosines, we have $B=cos^{-1}(\frac{(9)^2+(10)^2-(7)^2}{2(9)(10)})\approx42.8^\circ$
3. We have $C\approx(180-60.9-42.8)=76.3^\circ$
