Chapter 7 - Applications of Trigonometric Functions - Section 7.3 The Law of Cosines - 7.3 Assess Your Understanding - Page 559: 24

$b \approx3.61$ $A \approx 56.2^\circ$ $C\approx 33.8^\circ$

1. Use the Law of Cosines, we have $b=\sqrt {(3)^2+(2)^2-2(3)(2)cos90^\circ}\approx3.61$ 2. Use the Law of Sines, $\frac{sinA}{3}=\frac{sin90^\circ}{3.61}$, thus $A=sin^{-1}(\frac{3sin90^\circ}{3.61})\approx 56.2^\circ$ 3. We have $C\approx(180-90-56.2)=33.8^\circ$