Answer
$b \approx4.14$
$A \approx 43.0^\circ$
$C\approx 27.0^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $b=\sqrt {(3)^2+(2)^2-2(3)(2)cos110^\circ}\approx4.14$
2. Use the Law of Sines, $\frac{sinA}{3}=\frac{sin110^\circ}{4.14}$, thus $A=sin^{-1}(\frac{3sin110^\circ}{4.14})\approx 43.0^\circ$
3. We have $C\approx(180-110-43.0)=27.0^\circ$
