Answer
$A \approx36.3^\circ$
$B \approx26.4^\circ$
$C\approx 117.3^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $A=cos^{-1}(\frac{(6)^2+(3)^2-(4)^2}{2(6)(3)})\approx36.3^\circ$
2. Use the Law of Sines, $\frac{sinB}{3}=\frac{sin36.3^\circ}{4}$, thus $B=sin^{-1}(\frac{3sin36.3^\circ}{4})\approx26.4^\circ$
3. We have $C\approx(180-36.3-26.4)=117.3^\circ$
