Answer
$A \approx125.1^\circ$
$B \approx30.8^\circ$
$C\approx 24.1^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $A=cos^{-1}(\frac{(5)^2+(4)^2-(8)^2}{2(5)(4)})\approx125.1^\circ$
2. Use the Law of Sines, we have $\frac{sinB}{5}=\frac{sin125.1^\circ}{8}$
3. We have $B=sin^{-1}(\frac{5sin125.1^\circ}{8})\approx30.8^\circ$
4. We have $C\approx180-125.1-30.8=24.1^\circ$
