Answer
$A \approx97.9^\circ$
$B \approx52.4^\circ$
$C\approx 29.7^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $A=cos^{-1}(\frac{(8)^2+(5)^2-(10)^2}{2(8)(5)})\approx97.9^\circ$
2. Use the Law of Sines, $\frac{sinB}{8}=\frac{sin97.9^\circ}{10}$, thus $B=sin^{-1}(\frac{8sin97.9^\circ}{10})\approx52.4^\circ$
3. We have $C\approx(180-97.9-52.4)=29.7^\circ$
