Answer
$b \approx3.19$
$A \approx12.4^\circ$
$B\approx 147.6^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $b=\sqrt {(5)^2+(2)^2-2(5)(2)cos20^\circ}\approx3.19$
2. Use the Law of Sines, we have $\frac{sinA}{2}=\frac{sin20^\circ}{3.19}$
3. We have $A=sin^{-1}(\frac{2sin20^\circ}{3.19})\approx12.4^\circ$
4. We have $B\approx180-20-12.4=147.6^\circ$
