Answer
$c \approx3.75$
$A \approx32.1^\circ$
$B\approx 52.9^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $c=\sqrt {(3)^2+(2)^2-2(3)(2)cos95^\circ}\approx3.75$
2. Use the Law of Sines, we have $\frac{sinA}{2}=\frac{sin95^\circ}{3.75}$
3. We have $A=sin^{-1}(\frac{2sin95^\circ}{3.75})\approx32.1^\circ$
4. We have $B\approx180-95-32.1=52.9^\circ$
