Answer
$C \approx92.9^\circ$
$A \approx48.5^\circ$
$B\approx 38.6^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $C=cos^{-1}(\frac{(5)^2+(6)^2-(8)^2}{2(5)(6)})\approx92.9^\circ$
2. Use the Law of Sines, we have $\frac{sinA}{6}=\frac{sin92.9^\circ}{8}$
3. We have $A=sin^{-1}(\frac{6sin92.9^\circ}{8})\approx48.5^\circ$
4. We have $B\approx180-92.9-48.5=38.6^\circ$
