Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Section 7.3 The Law of Cosines - 7.3 Assess Your Understanding - Page 559: 20

Answer

$c \approx5.29$ $A \approx 79.2^\circ$ $C\approx 40.8^\circ$

Work Step by Step

1. Use the Law of Cosines, we have $c=\sqrt {(6)^2+(4)^2-2(6)(4)cos60^\circ}\approx5.29$ 2. Use the Law of Sines, $\frac{sinA}{6}=\frac{sin60^\circ}{5.29}$, thus $A=sin^{-1}(\frac{6sin60^\circ}{5.29})\approx 79.2^\circ$ 3. We have $C\approx(180-60-79.2)=40.8^\circ$
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