Answer
$A \approx127.2^\circ$
$B \approx32.1^\circ$
$C\approx 20.7^\circ$
Work Step by Step
1. Use the Law of Cosines, we have $A=cos^{-1}(\frac{(6)^2+(4)^2-(9)^2}{2(6)(4)})\approx127.2^\circ$
2. Use the Law of Sines, we have $\frac{sinB}{6}=\frac{sin127.2^\circ}{9}$
3. We have $B=sin^{-1}(\frac{6sin127.2^\circ}{9})\approx32.1^\circ$
4. We have $C\approx180-127.2-32.1=20.7^\circ$