Answer
$ 0$
Work Step by Step
$cos62^\circ-sin28^\circ=cos62^\circ-cos(90-28)^\circ=cos62^\circ-cos62^\circ=0$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 3
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