Answer
no triangle.
Work Step by Step
Use the Law of Cosines, $A=cos^{-1}(\frac{(3)^2+(1)^2-(2)^2}{2(3)(1)})=0$, thus no triangle.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 13
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