Answer
no triangle.
Work Step by Step
1. Use the Law of Sines $\frac{3}{sinA}=\frac{1}{sin110^\circ}=\frac{b}{sinB}$
2. Thus $A=sin^{-1}(\frac{3sin110^\circ}{1})\approx sin^{-1}(2.82)$, no solution, thus no triangle.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 10
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