Answer
$A \approx83.3^\circ$
$B\approx 44.0^\circ$
$C\approx 52.7^\circ$
Work Step by Step
1. Use the Law of Cosines, $A=cos^{-1}(\frac{(7)^2+(8)^2-(10)^2}{2(7)(8)})\approx83.3^\circ$
2. Use the Law of Cosines, $B=cos^{-1}(\frac{(10)^2+(8)^2-(7)^2}{2(10)(8)})\approx44.0^\circ$
3. Find the third angle $C\approx180-83.3-44.0=52.7^\circ$
