Answer
$A \approx39.6^\circ$
$B \approx18.6^\circ$
$C\approx 121.8^\circ$
Work Step by Step
1. Use the Law of Cosines, $A=cos^{-1}(\frac{(1/2)^2+(4/3)^2-(1)^2}{2(1/2)(4/3)})\approx39.6^\circ$
2. Use the Law of Cosines, $B=cos^{-1}(\frac{(1)^2+(4/3)^2-(1/2)^2}{2(1)(4/3)})\approx18.6^\circ$
3. Find the third angle $C\approx180-39.6-18.6=121.8^\circ$
