Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 19

Answer

$C=60^\circ$ $b \approx11.52$, $c \approx10.13$

Work Step by Step

1. Find the third angle $C=180-100-20=60^\circ$ 2. Use the Law of Sines $\frac{4}{sin20^\circ}=\frac{b}{sin100^\circ}=\frac{c}{sin60^\circ}$ 3. $b=\frac{4sin100^\circ}{sin20^\circ}\approx11.52$, $c=\frac{4sin100^\circ}{sin60^\circ}\approx10.13$
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