Answer
$0.32$
Work Step by Step
1. Find the third angle $C\approx180-50-30=100^\circ$
2. Use the Law of Sines $\frac{1}{sin50^\circ}=\frac{b}{sin30^\circ}$
3. $b=\frac{sin30^\circ}{sin50^\circ}\approx0.65$,
4. Use $b$ as the base, we have the area $K=\frac{1}{2}(0.65)(sin100^\circ)\approx0.32$
