Answer
$3.80$
Work Step by Step
1. Use the Law of Cosines, $A=cos^{-1}(\frac{(2)^2+(5)^2-(4)^2}{2(2)(5)})\approx49.5^\circ$
2. Use $b$ as the base, we have the area $K=\frac{1}{2}(2)(5sin49.5^\circ)\approx3.80$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 24
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