Answer
$1.93$
Work Step by Step
Use $b=3$ as the base, we have the height $h=a\ sinC=2sin40^\circ$, thus the area is $K=\frac{1}{2}(3)(2sin40^\circ)\approx1.93$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 21
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