Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 7 - Applications of Trigonometric Functions - Chapter Review - Review Exercises - Page 578: 16

Answer

$B\approx36.2^\circ$ $C\approx63.8^\circ$ $c\approx4.55$

Work Step by Step

1. Use the Law of Sines $\frac{5}{sin80^\circ}=\frac{3}{sinB}=\frac{c}{sinC}$ 2. Thus $B=sin^{-1}(\frac{3sin80^\circ}{5})\approx36.2^\circ$ 3. Find the third angle $C\approx180-80-36.2=63.8^\circ$ 4. $c=\frac{5sin63.8^\circ}{sin80^\circ}\approx4.55$
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