Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 5

Answer

$3$

Work Step by Step

Let $csc^{-1}\sqrt {10}=t$, we have $csc(t)=\sqrt {10}, sin(t)=\frac{1}{\sqrt {10}}, cos(t)=\frac{3}{\sqrt {10}}$, thus $cot(csc^{-1}\sqrt {10})=cot(t)=3$
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