Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 11

Answer

See below.

Work Step by Step

$LHS=\frac{csc\theta+cot\theta}{sec\theta+tan\theta} =\frac{csc\theta+cot\theta}{sec\theta+tan\theta}\times\frac{sec\theta-tan\theta}{sec\theta-tan\theta} =\frac{(csc\theta+cot\theta)(sec\theta-tan\theta)}{sec^2\theta-tan^2\theta} =(csc\theta+cot\theta)(sec\theta-tan\theta)$ $RHS=\frac{sec\theta-tan\theta}{csc\theta-cot\theta} =\frac{sec\theta-tan\theta}{csc\theta-cot\theta}\times\frac{csc\theta+cot\theta}{csc\theta+cot\theta} =\frac{(sec\theta-tan\theta)(csc\theta+cot\theta)}{csc^2\theta-cot^2\theta} =(sec\theta-tan\theta)(csc\theta+cot\theta)=LHS$
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