Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 14

Answer

See below.

Work Step by Step

$LHS=\frac{sin(\alpha+\beta)}{tan\alpha+tan\beta} =\frac{sin(\alpha+\beta)}{tan\alpha+tan\beta}\times\frac{cos\alpha cos\beta}{cos\alpha cos\beta} =\frac{sin(\alpha+\beta)cos\alpha cos\beta}{sin\alpha cos\beta+cos\alpha sin\beta} =\frac{sin(\alpha+\beta)cos\alpha cos\beta}{sin(\alpha+\beta)} =cos\alpha cos\beta =RHS$
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