Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 18

Answer

$2+\sqrt 3$

Work Step by Step

$tan75^\circ=tan(45+30)^\circ =\frac{tan45^\circ+tan30^\circ}{1-tan45^\circ tan30^\circ} =\frac{1+\sqrt 3/3}{1-\sqrt 3/3} =\frac{3+\sqrt 3}{3-\sqrt 3} =\frac{3+\sqrt 3}{3-\sqrt 3}\times\frac{3+\sqrt 3}{3+\sqrt 3} =\frac{12+6\sqrt 3}{6} =2+\sqrt 3$
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