Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 2

Answer

$ -\frac{\pi}{4}$

Work Step by Step

$sin^{-1}(-\frac{\sqrt 2}{2})=-sin^{-1}(\frac{\sqrt 2}{2})=-\frac{\pi}{4}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.