Answer
$ \frac{\pi}{6}$
Work Step by Step
$sec^{-1}(\frac{2}{\sqrt 3})=cos^{-1}(\frac{\sqrt 3}{2})=\frac{\pi}{6}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Chapter Test - Page 529: 1
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